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-   -   Can someone help me with a math problem? (http://www.insidehoops.com/forum/showthread.php?t=293556)

Boomerang 03-16-2013 02:01 PM

Can someone help me with a math problem?
 
i am kinda lost here.. the numbers i came up with didnt match any of the choices


steve franchise 03-16-2013 02:46 PM

Re: Can someone help me with a math problem?
 
You can't take exam II unless you pass I?

I'd go with D.

Boomerang 03-16-2013 02:58 PM

Re: Can someone help me with a math problem?
 
Quote:

Originally Posted by steve franchise
You can't take exam II unless you pass I?

I'd go with D.

Ahhhh thanks, with that in mind, I redid the calculations and got D as well. In my first calculations, I forgot to account for the previous passes. Thank you ver y much. :cheers:

steve franchise 03-16-2013 03:02 PM

Re: Can someone help me with a math problem?
 
No problem broski.

ace23 03-16-2013 03:05 PM

Re: Can someone help me with a math problem?
 
I got 448 like the first dude here:

http://translate.google.com/translat...ed=0CEIQ7gEwAQ

Don't understand how you get 565, though.

The Real JW 03-16-2013 03:22 PM

Re: Can someone help me with a math problem?
 
I got (A).

All of division A has failed at least 2 exams: 138*2 = 276
Those who took exam II (42 people) must have taken exam I first: 276 + 42 = 318
Those who took exam III (65 people) must have taken exams I and II first: 318 + 65*2 = 448

steve franchise 03-16-2013 03:38 PM

Re: Can someone help me with a math problem?
 
You were on the right track, you forgot 2 important steps. Add 138 (total number of trainees) and then subtract 21 (trainees who failed that year).

You get 565.

ripthekik 03-16-2013 03:47 PM

Re: Can someone help me with a math problem?
 
with a calculator, i did:

27+27+27
4+4
35+35+35+35
7+7+7
55+55+55+55+55
10+10+10+10
-----------------
565

CeltsGarlic 03-16-2013 03:51 PM

Re: Can someone help me with a math problem?
 
Alright , 4 more guys to say the same answer and we can call it a wrap.

Boomerang 03-16-2013 04:44 PM

Re: Can someone help me with a math problem?
 
This one has been driving me crazy too.



Now it's a huge trouble to do all the work, so I'm just going to ask you guys if you would approach it the same way I did. Which is for example Euro, I would take 1 and divide by 1.52 and 1.64 and see the difference of that. Do it for all currencies and see which number is the smallest?

Or do you just subtract the 1.64 and 1.52? (Seems too easy)

I've been out of school too long to remember proportional change :banghead:

By the way, this is not homework or anything. It's prep for numerical tests - you do them when you apply for a banking job. And you get 1 minute for each problem.

steve franchise 03-16-2013 05:07 PM

Re: Can someone help me with a math problem?
 
I would just subtract, but yeah it just seems too easy.

CeltsGarlic 03-16-2013 05:10 PM

Re: Can someone help me with a math problem?
 
The correct answer is subtract and compare. Its that easy.

brantonli 03-16-2013 05:28 PM

Re: Can someone help me with a math problem?
 
I'm pretty sure that's a question from a numerical test for graduate entry level jobs? I've done the same question before.

edit: lol didn't see the second question. Best of luck with these tests! If you get through to interview they randomly re-test people too so it's best to make sure you can do these yourself as well

ace23 03-16-2013 05:30 PM

Re: Can someone help me with a math problem?
 
I think the answer to the second question is A quickly subtracting.

The Real JW 03-16-2013 05:33 PM

Re: Can someone help me with a math problem?
 
Wouldn't proportional change be the percentage change relative to the base year 1?

EUR: +7.89%
USD: -9.38%
JPY: +20.25%
AUD: +6.27%
CHF: -7.69%
HKD: -8.94%
MYR: -28.29%

The smallest absolute value change being AUD?


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