I think you have to give credit to Denver, the chances of L.A taking both in Denver was always slim. At the end of the day the Lakers still have the advantage with homecourt back with two out of the 3 in L.A if needed.
Denver are a great team and deserve respect. L.A still will likely win this series in 6 IMO...Denver played a great game and deserved to win. They had to win and did so props to them.
I think you have to give credit to Denver, the chances of L.A taking both in Denver was always slim. At the end of the day the Lakers still have the advantage with homecourt back with two out of the 3 in L.A if needed.
Denver are a great team and deserve respect. L.A still will likely win this series in 6 IMO...Denver played a great game and deserved to win. They had to win and did so props to them.
True. Only I think its worse than that. I think the Lakers are just a little more injured and tired than the Nuggets and they are likely playing down some injuries (Lamar Odom and Ariza). The Nuggets have outplayed the Lakers in just about every quarter except the fourth quarter of the first three games. Thats worrying in and of itself.
I think you have to give credit to Denver, the chances of L.A taking both in Denver was always slim. At the end of the day the Lakers still have the advantage with homecourt back with two out of the 3 in L.A if needed.
Denver are a great team and deserve respect. L.A still will likely win this series in 6 IMO...Denver played a great game and deserved to win. They had to win and did so props to them.
I agree with this. That is why I still have hope for the Lakers.
Nuggets fans who get chance to see most of they`re games - are there any chances kleiza gets more minutes ( not the scenario if carmelo is injured ) and for all the others - what team could kleiza be in after summer?
pretty much agree with this. the nuggets outplayed the lakers and i wouldn't be surprised to see them take the series. the lakers look worn out, they have players injured, and no one is stepping up other than kobe/gasol on a consistent basis.