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Old 04-26-2011, 02:49 PM   #1
Sicknote
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Default Is this math problem solvable?

Very simple, I saw it on a friend's Facebook page. He doesn't know the answer but claims it can be done. I gave it a shot for about 20 minutes but couldn't come up with anything.

Use the numbers 1,2,3,4,5, AND 6 to get 96 using only addition, and only using each number once. You can combine the numbers to make another number (for example 1 and 2 to make 12). Remember you can only use the number once.

No negatives, fractions, or decimals allowed.

Last edited by Sicknote : 04-26-2011 at 02:55 PM.
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Old 04-26-2011, 02:52 PM   #2
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Default Re: Is this math problem solvable?

nm, just saw addition only
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Old 04-26-2011, 02:52 PM   #3
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Default Re: Is this math problem solvable?

Quote:
Originally Posted by answer
23 + 6 - 5 * 1 * 4 = 96

Using only addition.
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Old 04-26-2011, 02:53 PM   #4
SEEBASS1234
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Default Re: Is this math problem solvable?

65+31?
EDIT: ohppp nevermind. Sorry about that

Last edited by SEEBASS1234 : 04-26-2011 at 02:56 PM.
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Old 04-26-2011, 02:55 PM   #5
Sicknote
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Default Re: Is this math problem solvable?

Quote:
Originally Posted by SEEBASS1234
65+31?

You have to use all of the numbers.
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Old 04-26-2011, 03:04 PM   #6
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Default Re: Is this math problem solvable?

53+42+1=96

Pwned

****...just saw AND 6
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Old 04-26-2011, 03:09 PM   #7
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Default Re: Is this math problem solvable?

Quote:
Originally Posted by Hawker
53+42+1=96

I bet this is the answer. It's a trick question. I examined it for 5 minutes and I don't think it's plausible any other way.
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Old 04-26-2011, 03:20 PM   #8
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Default Re: Is this math problem solvable?

I don't think it's possible without some kind of trick. I keep on getting 93 though.
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Old 04-26-2011, 03:44 PM   #9
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Default Re: Is this math problem solvable?

I doubt there is a solution, let's look at it this way:
We have to get 6, in order to get 6 we can NOT use less than 3 numbers as we will then have to make 100(134+652) somewhere. We can NOT use more than 4 either as that would leave us with just 1 number to make the tens.
This means we will have to combine 3 or 4 numbers for 6.

This can be done as:
1+2+3, which leaves us with 40+50+60 = too much
There are no more solutions with 3 numbers as they would all exceed 6 and be less than 16 as 6+5+4=15
2+3+5+6 which leaves us with 10+40 = too little
1+4+5+6 which leaves us with 20+30 = too little
There are no more solutions for 4 as they can't reach 6(obviously) and if you do not use the 6 you can't get to 16: 5+4+3+2=14

I don't see a way to do this, but I might be wrong.
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Old 04-26-2011, 03:53 PM   #10
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Default Re: Is this math problem solvable?

If were looked at it from a trick question standpoint, it says to use 1-6 and only use them once but it doesn't specifically say your only limited to those numbers. So hypothetically, I guess you could use 7? I may be looking too much into this, I don't know.
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Old 04-26-2011, 04:00 PM   #11
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Default Re: Is this math problem solvable?

Don't think so if it's addition only.
Trick question?
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Old 04-26-2011, 04:46 PM   #12
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Default Re: Is this math problem solvable?

This is my theory:

It won't work because 5 is not a factor of 96, which is divisible by each of the other numbers.
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Old 04-26-2011, 04:54 PM   #13
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Default Re: Is this math problem solvable?

Closest I can get to is 93
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Old 04-26-2011, 04:56 PM   #14
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Default Re: Is this math problem solvable?

Quote:
Originally Posted by Sicknote
Very simple, I saw it on a friend's Facebook page. He doesn't know the answer but claims it can be done. I gave it a shot for about 20 minutes but couldn't come up with anything.

Use the numbers 1,2,3,4,5, AND 6 to get 96 using only addition, and only using each number once. You can combine the numbers to make another number (for example 1 and 2 to make 12). Remember you can only use the number once.
No negatives, fractions, or decimals allowed.

It might be a trick question?

14+56+23+3?

I combined the numbers to make another number and only used the number I made once. I dont know if combining counts as "using" the number or if it means you can only use it once in the addition?

I'm probably wrong but its just a thought.
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Old 04-26-2011, 05:05 PM   #15
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Default Re: Is this math problem solvable?

I think negatives have to be allowed and the answer is 65 + 43 + -12. That's the most logical conclusion I could come up with. It's either impossible or that's the answer.
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