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Old 10-12-2012, 08:51 PM   #31
raiderfan19
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Default Re: A riddle....

Quote:
Originally Posted by REACTION
Yeah, this is a tough (but good) problem. More than a riddle. I'm going to try to program something to help me compute all possible factorizations.
The addition has to add up to a number between 14 and 30. Honestly im starting to think this Isn't possible
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Old 10-12-2012, 09:32 PM   #32
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Default Re: A riddle....

Okay, I think I've narrowed it down to two possible combinations. You're right about the possible sums being between 14 and 30.

2-8-9-10 (Sum: 29, Product: 1440)
4-6-9-10 (Sum: 29, Product: 2160)

Here's a tabular output that shows all the combinations. I manually went through to rule out the impossible ones. But I'm stuck on narrowing it down to one solution. Hoping the OP shows up and either gives the answer or tells us whether multiple or no solutions exist. It kind of depends on Bob and the product.

Last edited by REACTION : 10-12-2012 at 09:37 PM.
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Old 10-12-2012, 10:06 PM   #33
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Default Re: A riddle....

Quote:
Originally Posted by REACTION
Okay, I think I've narrowed it down to two possible combinations. You're right about the possible sums being between 14 and 30.

2-8-9-10 (Sum: 29, Product: 1440)
4-6-9-10 (Sum: 29, Product: 2160)

Here's a tabular output that shows all the combinations. I manually went through to rule out the impossible ones. But I'm stuck on narrowing it down to one solution. Hoping the OP shows up and either gives the answer or tells us whether multiple or no solutions exist. It kind of depends on Bob and the product.

Not only copying a thread from 4chan, but taking credit for someone else's work
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Old 10-12-2012, 10:09 PM   #34
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Default Re: A riddle....

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Originally Posted by 28renyoy
Not only copying a thread from 4chan, but taking credit for someone else's work

If you're referring to the one on sci, I'm the creator. I'm posting there to get other ideas.
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Old 10-18-2012, 10:04 PM   #35
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Default Re: A riddle....

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Originally Posted by TheSilentKiller
Op We Need Answers
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Old 10-19-2012, 01:10 AM   #36
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Default Re: A riddle....

Quote:
Originally Posted by REACTION
Okay, I think I've narrowed it down to two possible combinations. You're right about the possible sums being between 14 and 30.

2-8-9-10 (Sum: 29, Product: 1440)
4-6-9-10 (Sum: 29, Product: 2160)

Here's a tabular output that shows all the combinations. I manually went through to rule out the impossible ones. But I'm stuck on narrowing it down to one solution. Hoping the OP shows up and either gives the answer or tells us whether multiple or no solutions exist. It kind of depends on Bob and the product.
This is correct
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