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Old 01-21-2014, 11:22 PM   #1
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Default ISH i need help with my homework...

Here is the question: The aluminum foil on a certain roll has a total area of 18.5m^2 and a mass of 1275g. Using a density of 2.7g/cc for aluminum, determine the thickness in millimeters of the aluminum foil.
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Old 01-21-2014, 11:27 PM   #2
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Default Re: ISH i need help with my homework...

mass = 1275g
density = 2.7g/cc
density = mass/volume
2.7g/cc = 1275g/volume
volume = 1275/2.7 = 472.2~cc
volume = area * thickness
472.2~ = 18.5m^2 * 10000cm^2/m^2 * thickness
thickness = 472.22cc/185000cm^2
thickness = 0.00255cm

Last edited by shaq2000 : 01-21-2014 at 11:30 PM.
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Old 01-21-2014, 11:37 PM   #3
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Default Re: ISH i need help with my homework...

thanks
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Old 01-21-2014, 11:41 PM   #4
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Default Re: ISH i need help with my homework...

No problem. I basically copy/pasted.
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Old 01-21-2014, 11:44 PM   #5
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Default Re: ISH i need help with my homework...

One question: where did you get this part?
10000cm^2/m^2 * thickness
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Old 01-21-2014, 11:48 PM   #6
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Default Re: ISH i need help with my homework...

Quote:
Originally Posted by Jameerthefear
One question: where did you get this part?
10000cm^2/m^2 * thickness

Converting the 18.5 m^2 into cubic centimeters.
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Old 01-21-2014, 11:50 PM   #7
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Default Re: ISH i need help with my homework...

Quote:
Originally Posted by Jameerthefear
One question: where did you get this part?
10000cm^2/m^2 * thickness

Area times thickness. The first part converts the square meters to square centimeters (10,000cm^2 = 1 m^2)
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Old 01-21-2014, 11:57 PM   #8
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Default Re: ISH i need help with my homework...

You have homework? School isn't canceled by snow where you live.
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Old 01-22-2014, 12:00 AM   #9
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Default Re: ISH i need help with my homework...

I can help you, but your son needs to learn from his own.
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